0=320x-5x^2

Solution for 0=320x-5x^2 equation:

0=320x-5x^2

We move all terms to the left:

0-(320x-5x^2)=0

We add all the numbers together, and all the variables

-(320x-5x^2)=0

We get rid of parentheses

5x^2-320x=0

a = 5; b = -320; c = 0;
Δ = b2-4ac
Δ = -3202-4·5·0
Δ = 102400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{102400}=320$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-320)-320}{2*5}=\frac{0}{10}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-320)+320}{2*5}=\frac{640}{10}
=64
$